Answer:
the capacitive reactance is reduced by a factor 2
Explanation:
The capacitive reactance is given by:
[tex]X_C = \frac{1}{2\pi f C}[/tex]
where
f is the frequency of the source
C is the capacitance
In this case, the frequency of the source is doubled:
f' = 2f
while the capacitance does not change. So the new capacitive reactance will be
[tex]X_C' = \frac{1}{2\pi f' C}=\frac{1}{2\pi (2f)C}=\frac{1}{2}X_C[/tex]
so the capacitive reactance is reduced by a factor 2.
