marcoadj
marcoadj marcoadj
  • 15-05-2019
  • Mathematics
contestada

Can anyone help with this please

Can anyone help with this please class=

Respuesta :

carlosego
carlosego carlosego
  • 15-05-2019

For this case we have a function of the form [tex]y = f (x)[/tex], where:

[tex]f (x) = \frac {5 + x} {6 + 3x}[/tex]

We must evaluate the function at[tex]x = a-1[/tex]

So:

[tex]g (a-1) = \frac {5+ (a-1)} {6 + 3 (a-1)}\\g (a-1) = \frac {5 + a-1} {6 + 3a-3}\\g (a-1) = \frac {4 + a} {3 + 3a}[/tex]

Thus, the value of the function is:

[tex]\frac {4 + a} {3 + 3a}[/tex]

Answer:

[tex]g (a-1) = \frac {4 + a} {3 + 3a}[/tex]

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