Answer:
The numbers are 44 and 46
Step-by-step explanation:
Let
x, x+2 ----> the two consecutive positive even integers
we know that
[tex](x+x+2)^{2} =4,048+x^{2} +(x+2)^{2} \\ \\(2x+2)^{2} =4,048+x^{2} +x^{2}+4x+4\\ \\4x^{2}+8x+4=2x^{2}+4x+4,052\\ \\2x^{2} +4x-4,048=0[/tex]
Solve the quadratic equation using a graphing calculator
The solution is x=44
see the attached figure
[tex]x+2=44+2=46[/tex]
therefore
The numbers are 44 and 46
