lala12018 lala12018

15-05-2019
Chemistry

contestada

What is the [OH-] of a solution whose pH=12.5

Respuesta :

meetpatel0719 meetpatel0719

15-05-2019

Answer:

0.316

Explanation:

ph --> H+ --> Oh-

H+ = 10^-ph

= 10^-12.5

= 3.16 x 10^-13

now for oh-

oh - = 1 x 10^-14 / 3.16 x 10^-13

= .0316

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