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  • 15-05-2019
  • Chemistry
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What is the [OH-] of a solution whose pH=12.5

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meetpatel0719
meetpatel0719 meetpatel0719
  • 15-05-2019

Answer:

0.316

Explanation:

ph --> H+ --> Oh-

H+ = 10^-ph

     = 10^-12.5

     = 3.16 x 10^-13

now for oh-

oh - =  1 x 10^-14 / 3.16 x 10^-13

       = .0316

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