Answer:
[tex](x-3)^{2} +(y+2)^{2}=9[/tex]
Step-by-step explanation:
we know that
the equation of a circle into center radius form is equal to
[tex](x-h)^{2} +(y-k)^{2}=r^{2}[/tex]
In this problem we have
center ( 3,-2)
radius r=3 units
substitute
[tex](x-3)^{2} +(y+2)^{2}=3^{2}[/tex]
[tex](x-3)^{2} +(y+2)^{2}=9[/tex]
