Answer:
13.39 mol ≅ 13.4 mol.
Explanation:
- It is known that 1.0 mole of any gas occupies 22.4 L at STP conditions.
Using cross multiplication:
1.0 mole of Cl₂ occupies → 22.4 L.
??? mole of Cl₂ occupies → 300.0 L.
∴ The no. of moles of Cl₂ are in 300 liters = (1.0 mol)(300.0 L)/(22.4 L) = 13.39 mol ≅ 13.4 mol.
