Answer:
see explanation
Step-by-step explanation:
These are the terms of a geometric sequence with n th term formula
[tex]a_{n}[/tex] = a [tex](r)^{n-1}[/tex]
where a is the first term and r the common ratio
r = [tex]\frac{-48}{64}[/tex] = [tex]\frac{36}{-48}[/tex] = - [tex]\frac{3}{4}[/tex]
the first term a = 64, hence
[tex]a_{n}[/tex] = 64 [tex](-3/4)^{n-1}[/tex]
