For this case we must find the product of the following expression:
[tex]-2x * (- 3x^2y) * (2y) =[/tex]
We take into account that:
[tex]- * - = +[/tex]
To multiply powers of the same base, the same base is placed and the exponents are added:
[tex]6x^{1 + 2}y * 2y =\\6x ^ 3 * 2y ^ {1 + 1} =\\12x ^ 3y ^ 2[/tex]
ANswer:
[tex]12x ^ 3y ^ 2[/tex]
Option A
