Answer:
The real zero is between 1 and 2.
Step-by-step explanation:
The given function is:
[tex]f(x)=x^3-2[/tex]
To find the zeros of this function, we set f(x)=0.
[tex]\implies x^3-2=0[/tex]
Add 2 to both sides to obtain:
[tex]\implies x^3=2[/tex]
Take the cube root of both sides
[tex]\implies x=\sqrt[3]{2}[/tex]
[tex]\implies x=1.26[/tex]
Therefore the real zero is between 1 and 2.
