Brainlymainly111 Brainlymainly111
  • 12-06-2019
  • Mathematics
contestada

Simplify. x/4x+x^2

a. 1/4
b. 1/4+x; where x= -4, 0
c. 1/4+x; where x= -4
d. 1/4x; where x= 0

Respuesta :

jdoe0001 jdoe0001
  • 12-06-2019

[tex]\bf \cfrac{x}{4x+x^2}\implies \cfrac{\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}{\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(4+x)}\implies \cfrac{1}{4+x}\qquad \{x|x\in \mathbb{R}, x\ne -4\}[/tex]

if you're wondering about the restriction of x ≠ -4, is due to that would make the fraction with a denominator of 0 and thus undefined.

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