Answer:
I = [tex]R^{2}[/tex](K+5)
Explanation:
Given :
J = k+5
Now selecting a thin ring in the wire of radius "r" and thickness dr.
Current through the thin ring is
dI = J X 2πrdr
dI = (K+5) x 2πrdr
Now integrating we get
I = [tex]\int_{0}^{R} = (K+5).2\pi rdr[/tex]
I = (K+5) 2π[tex]\int_{0}^{R} rdr[/tex]
I = (K+5) 2π [tex]\frac{R^{2}}{2}[/tex]
I = [tex]R^{2}[/tex](K+5)
