Answer:
The pressure the hydrogen gas exerted before its volume was decreased is 2.7207 atm.
Explanation:
Using Boyle's law
[tex] {P_1}\times {V_1}={P_2}\times {V_2}[/tex]
Given ,
V₁ = 14.65 L
V₂ = 7.94 L
P₁ = ?
P₂ = 5.02 atm
Using above equation as:
[tex]{P_1}\times {V_1}={P_2}\times {V_2}[/tex]
[tex]{P_1}\times {14.65}={5.02}\times {7.94}\ atm[/tex]
[tex]{P_1}=\frac {{5.02}\times {7.94}}{14.65}\ atm[/tex]
[tex]{P_1}=2.7207\ atm[/tex]
The pressure the hydrogen gas exerted before its volume was decreased is 2.7207 atm.
