For this case we must solve the following system of equations:
[tex]2x + y = 5\\3y = 15-6x[/tex]
We clear "y" from the second equation:
[tex]y = \frac {15} {3} - \frac {6x} {3}\\y = 5-2x[/tex]
We substitute in the first equation:
[tex]2x + (5-2x) = 5\\2x + 5-2x = 5\\5 = 5[/tex]
Equality is fulfilled, so for any value of x equality will be fulfilled.
So, the system has infinite solutions.
Answer:
Infinite solutions
