rebeccaisthefamous1 rebeccaisthefamous1
  • 15-08-2019
  • Mathematics
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Аноним Аноним
  • 15-08-2019

X^2 + 2x -4= 0

You need to remember one standard result

ax^2 + bx + c= 0

[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]

By Comparing the coefficients,

a= 1, b=2, c=-4

[tex]x = \frac{ - 2 + - \sqrt{ {2}^{2} - 4 \times 1 \times - 4 } }{2 \times 1} \\ x = \frac{ - 2 + - \sqrt{4 + 16} }{2} \\ \\ x = \frac{ - 2 + - \sqrt{20} }{2} \\ \\ x = \frac{ - 2 + - 2 \sqrt{5} }{2} \\ \\ x = - 1 + - \sqrt{5} [/tex]

Options A ,C

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