Seb17
Seb17
15-05-2016
Chemistry
contestada
Calculate the mass of 139 cm^3 Argon at STP
Respuesta :
Willchemistry
Willchemistry
16-05-2016
Volume in liters:
139 cm³ / 1000 = 0.139 L
molar mass Argon = 39.95 g/mol
1 mole -------- 22.4 L ( at STP )
? mole ------- 0.139 L
moles of argon :
0.139 * 1 / 22.4 = 0.00620 moles
Mass of argon :
0.00620 * 39.95 =
0.24769 g
hope this helps!
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