leelee9273 leelee9273

12-09-2019
Mathematics

contestada

r+10<-3(2r-3)+6(r+3)

Respuesta :

kusidesmo kusidesmo

12-09-2019

Answer:

{r:r<17}

Step-by-step explanation:

given r+10<-3(2r-3)+6(r+3)

change the < to = to solve the equation

thus, r+10=-3( 2r-3 )+6( r+3 )

r+10= -6r +9 +6r +18

r+10= 9+18

r+10=27

r=27-10

r=17

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