damaris40 damaris40
  • 13-09-2019
  • Mathematics
contestada

Make sure the fraction is fully reduced:
3y/13 + 7y/26

Make sure the fraction is fully reduced 3y13 7y26 class=

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mathstudent55
mathstudent55 mathstudent55
  • 13-09-2019

Answer:

[tex] \dfrac{y}{2} [/tex]

Step-by-step explanation:

The LCD of 13 and 26 is 26.

[tex] \dfrac{3y}{13} + \dfrac{7y}{26} = [/tex]

[tex] = \dfrac{2 \times 3y}{2 \times 13} + \dfrac{7y}{26} [/tex]

[tex] = \dfrac{6y}{26} + \dfrac{7y}{26} [/tex]

[tex] = \dfrac{13y}{26} [/tex]

[tex] = \dfrac{y}{2} [/tex]

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