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  • 13-09-2019
  • Physics
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A 5.0 c charge is 10 m from a small test charge. what is the magnitude of the electric field at the location of the test charge ?

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sebasacevedop
sebasacevedop sebasacevedop
  • 17-09-2019

Answer:

[tex]4.50*10^8\frac{N}{C}[/tex]

Explanation:

The electric field is generated by a charge and represents the force exerted on a test charge, that is, the electric force per unit of charge. Therefore the equation for the electric field can be obtained from Coulomb's law.

[tex]E=\frac{F}{q}\\E=\frac{kq}{r^2}\\E=\frac{5C*8.99*10^9\frac{Nm^2}{C^2}}{(10 m)^2}=4.50*10^8\frac{N}{C}[/tex]

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