Answer:
Step-by-step explanation:
Given that t A, B, and C are invertible matrices of the same
size.
To pr that [tex](ABC)^{-1} = C^{-1}B^{-1}A^{-1}.[/tex]
to pr that [tex]( ABC) (C^{-1}B^{-1}A^{-1})=e[/tex]
LS=[tex]( AB(C (C^{-1})B^{-1}A^{-1})\\=ABIB^{-1}A^{-1})\\=A(BB^{-1})A^{-1})\\=AA^{-1})\\=I[/tex]
Thus proved
