MissSmartyPants1102 MissSmartyPants1102
  • 14-09-2019
  • Physics
contestada

What is the de Broglie wavelength for a proton (m = 1.67× 10^−27 kg) moving at a speed of 9.50 × 10^6 m/s? (h = 6.63 × 10^−34 J⋅s)

Respuesta :

aristeus aristeus
  • 17-09-2019

Answer:

De broglie wavelength = 4.17 pm

Explanation:

We have given mass of proton [tex]m=1.67\times 10^{-27}kg[/tex]

Speed of proton v [tex]v=9.50\times 10^{6}m/sec[/tex]

Plank's constant [tex]h=6.63\times 10^{-34}J-s[/tex]

We have to find de broglie wavelength

De broglie wavelength is given by [tex]\lambda =\frac{h}{mv}=\frac{6.63\times 10^{-34}}{1.67\times 10^{-27}\times 9.5\times 10^6}=4.17\times 10^{-12}m=4.17pm[/tex]

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