hiii60
hiii60 hiii60
  • 14-09-2019
  • Mathematics
contestada

t varies inversely as the square root of u.
t = 3 when u = 4.
Find t when u = 49.​

Respuesta :

jimrgrant1 jimrgrant1
  • 14-09-2019

Answer:

t = [tex]\frac{6}{7}[/tex]

Step-by-step explanation:

Given that t varies inversely as the square root of u then the equation relating them is

t = [tex]\frac{k}{\sqrt{u} }[/tex] ← k is the constant of variation

To find k use the condition t = 3 when u = 4, thus

k = t[tex]\sqrt{u}[/tex] = 3 × [tex]\sqrt{4}[/tex] = 3 × 2 = 6

t = [tex]\frac{6}{\sqrt{u} }[/tex] ← equation of variation

When u = 49, then

t = [tex]\frac{6}{\sqrt{49} }[/tex] = [tex]\frac{6}{7}[/tex]

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