[tex]\bf f(x) = -4(x-3)^2+7\implies f(x) = -4(x-3)(x-3)+7 \\\\\\ f(x) = -4(\stackrel{\mathbb{F~O~I~L}}{x^2-6x+9})+7\implies f(x) = (-4x^2+24x-36)+7 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill f(x) = -4x^2+24x-29~\hfill[/tex]
Answer:
y = -4x^2 +24x - 29
Step-by-step explanation:
Standard notation
