Answer:
The value of the given equation[tex]x+3y+z[/tex] is 16
Solution:
Given values are x=3; y=3; z=4
To find: the value of [tex]x+3y+z[/tex]
On substituting the given values of x, y and z in the equation,
we get, [tex]3+(3\times3)+4[/tex]
[tex]\Rightarrow 3+9+4 = 16[/tex]
Hence, the value of [tex]x+3y+z[/tex] is 16
