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1.You wish to make a 0.325 M hydrochloric acid solution from a stock solution of 3.00 M hydrochloric acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution? in ml

2.In the laboratory you dilute 4.35 mL of a concentrated 12.0 M perchloric acid solution to a total volume of 50.0 mL. What is the concentration of the dilute solution?M

Respuesta :

Answer:

5.42 mL needed to be added and 1.04 M of dilute solution

Explanation:

For both cases, you need to use the expression:

M1*V1 = M2*V2

where M and V are concentration and volume.

For the 1st question, we have both concentrations, but we do not have both volume so:

3 * V1 = 0.325 * 50

V1 = 0.325 * 50 / 3

V1 = 5.42 mL need to be added.

For question 2:

Same as above, with the difference that we need to calculate concentration so:

12 * 4.35 = M2 * 50

M2 = 12 * 4.35 / 50

M2 = 1.04 M is the concentration of the diluted solution

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