For this case we must resolve the following inequality:
[tex]- \frac {3} {2} <3x[/tex]
So, if we divide by 3 on both sides of the equation we have:
[tex]\frac {- \frac {3} {2}} {3} <\frac {3x} {3}\\- \frac {1} {2} <x[/tex]
Thus, the solution is given by all the values of "x" greater than [tex]- \frac {1} {2}[/tex]
Answer:
The solution to inequality is:
([tex]- \frac {1} {2}[/tex];∞)
