maddiemccleary2882 maddiemccleary2882
  • 15-11-2019
  • Mathematics
contestada

A polynomial has been factored below but some constants are missing 2x³-8x²-24x=ax(x+b)(x+c)

Respuesta :

rani01654 rani01654
  • 19-11-2019

Answer:

a = 2, b = - 6 and c = 2

Step-by-step explanation:

We have to express the polynomial 2x³ - 8x² - 24x in factored form.

So, we have to express it in 2x³ - 8x² - 24x = ax(x + b)(x + c) form where we have to identify the values of constants a, b, and c.

Now, 2x³ - 8x² - 24x

= 2x ( x² - 4x - 12)

= 2x [x² - 6x + 2x - 12]

= 2x (x - 6)(x + 2)

Now, comparing 2x (x - 6)(x + 2) with ax(x + b)(x + c) we get, a = 2, b = - 6 and c = 2 (Answer)

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