Reaction 1: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g), ΔH1=−2043 kJ
Reaction 2: 3C3H8(g)+15O2(g)→9CO2(g)+12H2O(g), ΔH2=?

Find H2

Question

11-06-2016
Chemistry

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Reaction 1: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g), ΔH1=−2043 kJ
Reaction 2: 3C3H8(g)+15O2(g)→9CO2(g)+12H2O(g), ΔH2=?

Find H2

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Аноним Аноним · Answer 1 · 2016-06-21T15:44:23+02:00

Аноним Аноним

21-06-2016

Given teh equation adn the heat of reaction, reaction 2's heat of reaction can be obtained by simply multiplying teh heat of reaction of 1 by 3. The final answer is -6129 kJ.

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Reaction 1: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g), ΔH1=−2043 kJ Reaction 2: 3C3H8(g)+15O2(g)→9CO2(g)+12H2O(g), ΔH2=? Find H2

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Reaction 1: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g), ΔH1=−2043 kJ
Reaction 2: 3C3H8(g)+15O2(g)→9CO2(g)+12H2O(g), ΔH2=?

Find H2