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caylus
Hello,

The tangent point T is (-2,a(-2)^3) or (-2,b-3*(-2))
The slope of the curve in T is -3 (slope of the line)

y=ax^3==>y'=3ax²==>y'(-2)=3*a*4=-3 ==>4a=-1 ==>a=-1/4

T=(-2,-1/4*(-2)^3))=(-2,2)

b-3*(-2)=2==>b=2-6==>b=-4



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