contestada

the equation below describes a circle. what are the coordinates of the center of the circle?
(x+5squared)+(y+2squared)=21 squared

Respuesta :

Hagrid
Since, the equation involved is a circle let us clearly write the equation first:
[tex](x+5)^2+(y+2)^2=21^2[/tex]

From the standard equation of the circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
[tex](h,k)=(x,y)[/tex]

So from the equation given above, our x would be -5, and our y is equivalent to -2.
So the center of our circle is located at the point (-5,-2)

Answer:

(-5,-2)

Step-by-step explanation:

the equation involved is a circle let us clearly write the equation first:

From the standard equation of the circle:

So from the equation given above, our x would be -5, and our y is equivalent to -2.

So the center of our circle is located at the point (-5,-2)