LaToyaShante7015 LaToyaShante7015

13-12-2019
Physics

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A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 500 V. The rate at which electrical energy is dissipated in the resistor is 286 W. What is the impedance Z of the circuit?

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obasola1 obasola1

13-12-2019

Answer:

Explanation:

impedance z=(XL^2+R^2)^1/2

power across te resistor ==i^2r

286/300

I=.976

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