AuzhuricBailey32 AuzhuricBailey32
  • 13-12-2019
  • Mathematics
contestada

In quadrilateral ABCD, m< ACD= 2x + 4 and m< ACB= 5x - 8. For what value of x is ABCD a rhombus?

Respuesta :

rani01654 rani01654
  • 20-12-2019

Answer:

x = 4

Step-by-step explanation:

If a quadrilateral is a rhombus, then the diagonals of it will bisect each angle of the quadrilateral.

Now, the diagonal AC bisects angle C into ∠ ACD and ∠ ACB.

Hence, ∠ ACD = ∠ ACB

⇒ 2x + 4 = 5x - 8 {Given that ∠ ACD= 2x + 4 and ∠ ACB= 5x - 8 }

⇒ 3x = 12

⇒ x = 4 (Answer)

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