Answer:
Volume of the chlorine gas is 0,056 m³.
Explanation:
p × V = n × R ×T
p = 101325 Pa
n = 2,5 moles
R = 8,31446 J K⁻¹ moles⁻¹
T = 273,15 K
(standard conditions)
V = ( n × R × T ) / p = ( 2,5 moles × 8,31446 J K⁻¹ moles⁻¹ × 273,15 K) / 101325 Pa
V = 0,056 m³
