jrbfrbgfrlgfboiwbfb4 jrbfrbgfrlgfboiwbfb4
  • 14-12-2019
  • Physics
contestada

A 175-kg motorcycle goes around an unbanked turn of radius 75.4 m at a steady 112 km/h. Determine its acceleration?

Answer

Respuesta :

cryssatemp
cryssatemp cryssatemp
  • 26-12-2019

Answer: [tex]12.83 m/s^{2}[/tex]

Explanation:

In this case we are talking about the centripetal acceleration [tex]a_{c}[/tex], which can be calculated by:

[tex]a_{c}=\frac{V^{2}}{r}[/tex]

Where:

[tex]V=112 \frac{km}{h} \frac{1000 m}{1 km} \frac{1h}{3600 s}=31.11 m/s[/tex] is the speed of the motorcycle

[tex]r=75.4 m[/tex] is the radius of the path the motorcycle is going around

Solving:

[tex]a_{c}=\frac{(31.11 m.s)^{2}}{75.4 m}[/tex]

Finally:

[tex]a_{c}=12.83 m/s^{2}[/tex]

Answer Link

Otras preguntas

What is the silk road? What valuable products were traded on the silk road?
What is the silk road? What valuable products were traded on the silk road?
What is the silk road? What valuable products were traded on the silk road?
What is the silk road? What valuable products were traded on the silk road?
What is the silk road? What valuable products were traded on the silk road?
What is the silk road? What valuable products were traded on the silk road?
What is the silk road? What valuable products were traded on the silk road?
What is the silk road? What valuable products were traded on the silk road?
What is the silk road? What valuable products were traded on the silk road?
What is the silk road? What valuable products were traded on the silk road?