I would break it into groups. Basically that means split -26x into 2 different numbers that added together will equal -26x. That way, you can easily factor.
[tex]48x^2-26x+3[/tex]
Im going to use -8x and -18x
[tex](48^2-8x)+(-18x+3)[/tex]
now you factor out the LCD in each of the parenthesis.
[tex](48^2-8x)=8x(6x-1)[/tex]
[tex](-18x+3)=-3(6x-1)[/tex]
since they both have [tex](6x-1)[/tex]
you can factor that out.
Making the answer be:
[tex](8x-3)(6x-1)[/tex]
