Respuesta :

Answer:

I =62.5 μ A

Explanation:

Given that

Charge ,q = 2.5 x 10⁻³ C

time ,t= 40 s

We know that current I given as

[tex]I=\dfrac{q}{t}[/tex]

Now by putting the values in the above equation we get

[tex]I=\dfrac{2.5\times 10^{-3}}{40}\ C/s[/tex]

We know that

1 A = 1 C/s

Therefore the current I will be

I=0.0000625 A

I = 0.0625 m A

The current in μ A will be

I =62.5 μ A

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