TheLegendMan7175 TheLegendMan7175
  • 14-01-2020
  • Physics
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Light from a laser forms a 1.31-mm diameter spot on a wall. If the light intensity in the spot is what is the power output of the laser?

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boffeemadrid
boffeemadrid boffeemadrid
  • 14-01-2020

Answer:

0.04973 W

Explanation:

I = Intensity of laser = [tex]3.69\times 10^4\ W/m^2[/tex] (assumed, as it is not given)

d = Diameter of spot = 1.31 mm

r = Radius = [tex]\dfrac{d}{2}=\dfrac{1.31}{2}\ mm[/tex]

A = Area = [tex]\pi r^2[/tex]

Power is given by

[tex]P=IA\\\Rightarrow P=3.69\times 10^4\times \pi \dfrac{(1.31\times 10^{-3})^2}{4}\\\Rightarrow P=0.04973\ W[/tex]

The power output of the laser is 0.04973 W

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