Answer:
[tex] 12 = e^{2.4849}[/tex]
Step-by-step explanation:
For this case we have the following expression:
[tex] ln(12) = 2.4849[/tex]
We need to remember that the natural log and the exponentiation with the base the euler number e are inverse operations, and if we apply exponentiation on both sides of the equation we got this:
[tex] e^{ln(12)} = e^{2.4849}[/tex]
We have the identity operator for this [tex]e^{ln(x)}= x[/tex]
[tex] 12 = e^{2.4849}[/tex]
And that would be our final answer for this case.
