Answer: 147kpa
Explanation:
Guage pressure may be defined as the difference between the pressure of a system and its surrounding.
Guage pressure P can be written as.
P = pgh
Where p = density, g = acceleration due to gravity, h = depth
For, guage pressure P1 and P2.
P1 /P2 = p1g1h1/p2g2h2
Since it's the same liquid p1 =p2 and g1 = g2
P1/P2 = h1/h2
P2 = P1h2/h1
P1 = 49kpa
h1 = 3m
h2 = 9m
P2 = 49×9/3
P2 = 147kpa
Therefore, the gage pressure in the same liquid at a depth of 9 m is 147kpa.
