Answer:
the function f(x) = (x+1)/(x^2-4) is discontinuous at x=2 and at x=-2
Step-by-step explanation:
The function is discontinuous at the roots of the denominator x^2-4, which are at x=2 and x=-2.
The function f(x) =(x+1)/(x^2-4) has also two vertical asymptotes at these points.
The Graph of the function is attached. One horizontal asymptote can also be identified at y=0
