Respuesta :

princessesther2011

Answer:

dy/dx = 2x+1/x(x+1)

Step-by-step explanation:

y = In x(x+1)

Let u = x(x+1) = x^2 + x

du/dx = 2x + 1

y = In u

dy/du = 1/u

dy/dx = dy/du × du/dx = 1/u × 2x+1 = 2x+1/u = 2x+1/x(x+1)

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