They are consecutive *odd* integers. So,
if the first integer is a,
then the second one is a+2
and the third one is a+4.
And we know that
a + a+2 + a+4 = 33
We can find what a is, and that is the smallest number. Then to find the other two, just count up from a.
a + a+2 + a+4 = 33
3a + 6 = 33
a = (33-6)/3 = 9
So the integers are 9, 11, and 13.
Indeed, 9+11+13=33
