rabideaubm rabideaubm
  • 11-02-2020
  • Mathematics
contestada

Solve 5^x-3 = 3^2x+1 (round to the nearest hundredth)

Respuesta :

surjithayer10 surjithayer10
  • 12-02-2020

Answer:

Step-by-step explanation:

if [tex]5^{x-3} =3^{2x+1} \\(x-3)log 5=(2x+1)log 3\\x log 5-3 log 5=2 x log 3+log 3\\x(log 5-2 log 3)=log 3 +3 log 5\\x=\frac{log 3+3 log 5}{log 5-2 log 3} \\\\x \approx -10.08[/tex]

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