nencyrpatel nencyrpatel
  • 12-02-2020
  • Mathematics
contestada

What is the solution

What is the solution class=

Respuesta :

surjithayer10 surjithayer10
  • 13-02-2020

Answer:

Step-by-step explanation:

[tex]\sqrt{2x+4} -\sqrt{x} =2\\\sqrt{2x+4} =2+\sqrt{x} \\squaring\\2x+4=4+x+4\sqrt{x} \\2x+4-4-x=4\sqrt{x} \\x=4\sqrt{x} \\again~squaring\\x^2=16x\\x^2-16x=0\\x(x-16)=0\\x=0,16[/tex]

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