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Race cars A and B are driving on the same circular racetrack at the same speed of 45.0 m/s. At a given instant car A is on the north side of the track moving eastward and car B is on the south side of the track moving westward. Find the magnitude of the velocity vector of car A relative to car B.

Respuesta :

Answer:90 m/s

Explanation:

Given

Speed of both the car is [tex]v=45\ m/s[/tex]

Suppose North side and East side as Positive Y and x axis

so Velocity of car A can be written as

[tex]v_a=45\hat{i}[/tex]

Velocity of car B is

[tex]v_b=-45\hat{i}[/tex]

Velocity of car A relative to car B is given by

[tex]v_{ab}=v_a-v_b[/tex]

[tex]v_{ab}=45\hat{i}-(-45\hat{i})[/tex]

[tex]v_{ab}=90\hat{i}[/tex]

Magnitude of velocity is

[tex]|v_{ab}|=90\ m/s[/tex]

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