Answer:
[tex]4.388*10^-^2^1[/tex]
Explanation:
Given:
[tex]N/V= 106 atoms/m^3[/tex]
[tex]T=3.0K[/tex]
we know the values of
[tex]K_{b} =1.38*10^-^2^3 J/K[/tex]
[tex]N_{A} =6.02*10^2^3/mol[/tex]
Formula:
[tex]PV=NK_{b} T[/tex]
rearranging the formula and substituting values
[tex]P=(NK_{b} T)/V[/tex]
[tex]P=(106)(1.38*10^-^2^3)(3)[/tex]
[tex]P=4.388 *10^-^2^1 Pa[/tex]
