Explanation:
The pH of the solution is 9.63 ± 0.03.
we know that
pH= -log[H+]
⇒[H+] =[tex]10^{-pH}[/tex]
=[tex]10^{-9.63}[/tex] = [tex]2.34\times10^{-10}[/tex]
Now to find absolute error we use the formula
Absolute error/[H+] =ln10(uncertainity)
Absolute error = ln10×[H+] ×0.03
[tex]=ln10\times2.34\times10^{-10}\times0.03[/tex]
= [tex]9.45\times10^{-12}[/tex]
