Answer:
225 m.
Explanation:
Applying the equation of motion.
v² = u²+2as..................... Equation 1
Where v = final velocity of the car, u = initial velocity of the car, a = acceleration of the car, s = distance traveled by the car.
make s the subject if the equation.
s = (v²-u²)/2a.................... Equation 2
Given: v = 0 m/s, u = 30 m/s, a = -2 m/s²
Substitute into equation 2
s = (0²-30²)/(-2×2)
s = -900/-4
s = 225 m.
Hence the maximum distance the car travels up the hill = 225 m.
