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A group of people were asked, “If you had a choice of an SUV or a sports car, what would you choose?” Of those surveyed, 30% were men, 70% were women. Of the women surveyed, 60% would choose an SUV. If a person is selected at random, what is the probability the person is a woman who would choose an SUV?

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TaeKwonDoIsDead

Answer:

42%

Step-by-step explanation:

Lets assume there were a total of 100 people (it will make calculations much easier).

Given, 30% men and 70% women, so we can say:

30% of 100 = 30 Men

70% of 100 = 70 Women

OF THE WOMEN SURVEYED, 60% of those prefer SUV. So,

60% of 70 (women) prefer SUV,

60/100 * 70 = 0.6 * 70 = 42 Women prefer SUV

We need probability of Woman prefering SUV from TOTAL, so that would make it:

42/100 = 0.42

Converting to percentage:

0.42 * 100 = 42%

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