gafadart1234 gafadart1234
  • 13-03-2020
  • Mathematics
contestada

Given that cosθ=3/5 in quadrant 3, fin sinθ

Respuesta :

ujalakhan18
ujalakhan18 ujalakhan18
  • 13-03-2020

Answer:

Sin theta =4/5

Step-by-step explanation:

Cos theta=base/HYPOTENUSE=3/5

Hence

From here we get

Base=3,HYPOTENUSE =5

By Pythagoras theorem

Hypotenuse ²=base²+perp²

5²=3²+perpendicular²

25=9+perp²

Perp²=25-9

Perp ²=16

Perp=4(taking sq root on both sides)

Now

Sin theta=perp/hyp=4/5

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