akshat74 akshat74
  • 15-03-2020
  • Mathematics
contestada

sec^4o- tan^4o = 1+2 tan^2o

sec4o tan4o 12 tan2o class=

Respuesta :

jimrgrant1 jimrgrant1
  • 15-03-2020

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

sec²x = tan²x + 1

Consider left side

[tex]sec^{4}[/tex] Θ - 4[tex]tan^{4}[/tex] Θ

= (tan²Θ + 1)² - 4[tex]tan^{4}[/tex]Θ ← expand factor using FOIL

= [tex]tan^{4}[/tex]Θ + 2tan²Θ + 1 - 4[tex]tan^{4}[/tex]Θ ← collect like terms

= 1 + 2tan²Θ = right side thus verified

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